How to find initial velocity of a car which is stopped in 10 seconds?

How to find initial velocity of a car which is stopped in 10 seconds?

1. v=u+at.
2. ⇒ 0=u+(−2.5)×10.
3. ∴ u=25m/s.

When a car starts from rest and attains a velocity of 10 meters per second in 40 seconds?

Expert-Verified Answer A driver starts the car from rest and attains a velocity of 10m/s in 40s and applies breaks and slows down the car to 5m/s in 10s. We have to find the acceleration of the car in both cases. Hence, the acceleration of the car in both cases is 0.25 m/s²and -0.5 m/s².

What was the acceleration of the car moving initially at 30 m s comes gradually to a stop in 900 m?

Expert-Verified Answer. The acceleration of the car is 0.5 meters per seconds square. Given the following data: Initial velocity, U = 30 m/s.

What is the formula for retardation?

Hence, the expression for retardation is a = v − u t , when u > v . What is meant by retardation? What is retardation.

What is the formula for initial velocity?

Let us take a quick look at those formulas. The first formula to find initial velocity is u = v – at.

How do I find initial velocity?

1. u = v – at. …
2. u² = v² – 2as. …
3. Where, …
4. Initial Velocity Solved Examples. …
5. Problem 1: Johny completes the bicycle ride with the final velocity of 10 ms^–1 and acceleration 2 ms^–2 within 3s. …
6. Answer: …
7. v (Final velocity) = u + at. …
8. ∴ (Initial velocity) u = 4ms^–1

What is the final velocity of a car that accelerated 10m s 2 from rest and traveled 180m?

What is the final velocity of a car that accelerated 10 m/s2 from rest and traveled 180m? V2=u2+2ad=zero2+2*10*180, v2=3600, so v=60 m/s.

What is the acceleration in SI units of car starts from rest and attains a velocity of 18 km h in 2sec?

Final velocity (v) = 18 km/h = (18 * 5 / 18) = 5m/s. Time taken (t) = 2 sec. ⇒ a = 2.5 m/s². Hence, the acceleration acquired by the car is 2.5 m/s².

What is the acceleration of a car moving at a constant velocity of 30m s?

A car is moving at a constant speed of 30 m/s in a straight line. The acceleration of the car is zero.

What is the formula for acceleration slowing down?

As mentioned in the previous section, one of the most common formulas that will be encountered when dealing with deceleration is: a = Δ v Δ t = v − v 0 t − t 0 , where a is the acceleration/deceleration, v is the final velocity, v is the initial velocity, t is the final time, and t is the initial time.

What is the acceleration of a car that starts from rest and travels 100 m in 5 s?

Hence, the value of acceleration is 8 m s – 2 . (b) A body starting from rest travels with uniform acceleration. If it travels 100 m in 5 s, what is the value of acceleration?

What is the acceleration of a car that goes from 0 to 60 in 5 seconds?

Explanation: 0 to 60 miles per hour means 0 to 88 feet/sec in five seconds (60 multiplied by 5280 (feet in one mile) divided by 3600 (seconds in an hour). Hence acceleration is 17.6 feet / second ^2.

What is the velocity of the car at the end of the 10 seconds?

Explanation: the car was initially at rest so the initial velocity is 0. Thus,the position of car at the end of 10s is 400m far from its initial position. Thus the velocity of the car at the end of 10s is 80m/s 80 m/s.

Can a car moving with a velocity of 10m s can be stopped?

A car moving with a velocity of 10m/s can be stopped by the application of a constant focal F in a distance of 20m. If the velocity of the car is 30m/s, it can be stopped by this force in. A car of mass 1500kg is moving with a certain velocity, u.

What is the velocity of a stopped car?

We know the final velocity is zero because the car has stopped.

How do you find the velocity after t seconds?

• Work out which of the displacement ( s ), initial velocity ( u ), acceleration ( a ), and time ( t ) you have to solve for the final velocity ( v ).
• If you have u , a , and t , use: v = u + at.
• If you have s , u , and t , use: v = 2(s/t) − u.
• If you have s , a , and t , use: