How do you find the kinetic energy of a mass of 2 kg?

How do you find the kinetic energy of a mass of 2 kg?

Kinetic energy=12mv2=12×2×102 =100 kgm2s−2=100 J. Q. The kinetic energy of a body of mass 2kg moving with a speed of 10ms−1 is: Q.

What percentage of kinetic energy of a moving particle is transferred to a stationary?

=(1−925)12mυ2×10012mυ2=64%

What are the characteristics of an elastic collision?

What is an elastic collision? An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision. Both momentum and kinetic energy are conserved quantities in elastic collisions.

See also  What is CBM and TBM?

What is the kinetic energy of a block of mass 2kg?

Kinetic energy=p22m=4.522×2=5.06 J. Q. A block of mass 2 kg is free to move along x-axis. It is at rest and t=0 on wards it is subjected to time dependent force F(t) in the x-direction.

What is the final formula for kinetic energy?

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

What percentage of kinetic energy of a moving particle is transferred 4 times?

Hence, \[64\% \] of K.E of a moving particle is transferred to a stationary particle when it strikes the stationary particle of 4 times its mass. Note: Momentum, the product of the mass of a particle and its velocity.

Is kinetic moving or stationary?

Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force.

What is the total kinetic energy of all moving particles within an object?

Thermal energy is the sum of the kinetic and potential energy of all the particles in an object.

What are the 3 types of collision?

  • Perfectly elastic collision.
  • Inelastic collision.
  • Perfectly inelastic collision.

Is momentum always conserved?

Momentum is always conserved because there is no external force acting on an isolated system (like the universe). Since momentum can never change, all of its components will always remain constant. Problems brought on by collisions should be resolved using the rule of conservation of momentum.

See also  How much do movers cost Minneapolis?

What are 3 examples of elastic collisions?

  • When we throw a ball on the floor, it bounces back. This is an example of elastic collision where both momentum and kinetic energy are conserved.
  • The collision between the atoms is also an example of elastic collision.
  • The collision between two biliard balls is an example of elastic collision.

What is a block of mass 2 kg initially at rest moves under?

A block of mass 2 kg initially at rest moves under the action of an applied horizontal force of 6 N on a rough horizontal surface. The coefficient of friction between block and surface is 0.1. The work done by the applied force in 10 s is (Take g=10 ms−2).

What is the energy of 1kg of mass?

This implies, for instance, that 1 kilogram of matter is equivalent to an energy E = (1 kg)×(3×108 m/sec)2 = 9×1016 kg m2/sec2. An energy of 1 kg m2/sec2 is known as 1 joule, for short.

What is the velocity of a body of mass 2kg moving in the xy plane?

Velocity of a body of mass 2 kg moving in x-y plane is given by v⃗ =(2i^+4tj^)m/s, where t is the time in second.

What is the kinetic energy of a body of mass 2 kg moving with a velocity of 0.1 ms 1?

The correct answer is: 0.01 J.

What is the kinetic energy of a body of mass 2 kg moving with a velocity of 0.1 ms?

Expert-Verified Answer K.E = 0.01 J. Hence, the kinetic energy of a body is 0.01 Joule.

What is the energy equivalent of a mass of 2kg?

Answer and Explanation: The amount of energy equivalent to two kilogram of mass at rest is 1.8 × 10 17 J .

See also  How do you move when you can't drive?

What is the kinetic energy of a body of mass 1 kg?

Given: Mass (m)= 1 kg. Velocity (v)= 10 m/s. ∴The Kinetic Energy of the object is 50 J.

Add a Comment