How much work is done to stop a car weighing 1500 kg moving with a speed of 60 km h?

How much work is done to stop a car weighing 1500 kg moving with a speed of 60 km h?

Hence, work required to stop the car =12×1500×16.662 =208166.7J=208.17kJ. Was this answer helpful?

What is the kinetic energy of a 1500 kg car moving at 20 ms?

Therefore, the kinetic energy of the car is 300,000 J.

What is the kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 ms?

The mass is 0.5 kg and the velocity is 10 meters per second. So: KE = (1/2)(0.5)(10)^2. Thus the kinetic energy of the ball is 25 J.

On what feature of the object does the amount of kinetic energy an object has depends on?

Kinetic energy depends on the velocity of the object squared. This means that when the velocity of an object doubles, its kinetic energy quadruples.

What is the work to be done to stop a car of 1500 kg moving at a velocity of 16 km per hour?

∴ The work done to stop the moving car = 208333 J.

What amount of work is done to stop a car of 1000 kg moving with a speed of 72 km per hour?

W = 1 2 × 1000 × 20 × 20 = 400000 J.

How do you calculate the kinetic energy of a car of mass 500 kg moving with a velocity?

Velocity of car, v = 36 km/hr = 36 × (5/18) = 10 m/s. Mass of car , m = 500 kg. Kinetic energy = (1/2) m v2 = (1/2) × 500 × 10 × 10 = 25000 J = 25 kJ.

What is the kinetic energy of a car of mass 1000 kg moving at 20 ms 1?

By using the equation: Kinetic Energy = (1/2)mv^2, using m as 1000kg and v as 20ms^-1. We can calculate this value as follows: KE = (1/2)(1000)(20)^2This is equal to 2.0*10^5J (solved using a scientific calculator).

What is the momentum of 1000 kg car moving northward at 20 m?

p = mv = (1000kg)(20m/s) = 20000 kg m/s, northward • c.

What is a mass of 1 kg is thrown up with a kinetic energy of 50j?

We will apply the concept of the conservation principle. Since 10% of energy is lost in overcoming air resistance. Then only 90% of kinetic energy will be left which then will be converted to potential energy. Hence, the height to which the body will rise is 4.5m.

What is the formula for kinetic energy?

Kinetic energy is energy possessed by an object in motion. The earth revolving around the sun, you walking down the street, and molecules moving in space all have kinetic energy. Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2.

What is the kinetic energy of a 5kg ball dropped from a height of 10m?

Answer and Explanation: Thus, the kinetic energy just before the ball reaches the ground is 490.5 J. The velocity of the ball before it reaches the ground is 14.0 m/s.

What are two examples of objects with kinetic energy?

A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work.

What is the difference between kinetic and potential energy?

Potential energy is the stored energy in any object or system by virtue of its position or arrangement of parts. However, it isn’t affected by the environment outside of the object or system, such as air or height. On the other hand, kinetic energy is the energy of an object or a system’s particles in motion.

What are the 2 things that objects depend on for kinetic energy?

Explain that there are two factors that affect how much kinetic energy a moving object will have: mass and speed.

How much work must be done to stop a 1000 kg car Travelling at 100km * H 1?

Hence, 385864 J work must be done to stop a traveling car.

What is the work required to be done to stop a car of 1200 kg moving with a velocity of 54 km per hour?

Expert-Verified Answer Thus the Work required to stop the car is -135,000 Joule or -135 kilo Joule.

How much work must be done to stop a 925 kg car moving with speed 95 km h?

The work to stop the car can be calculated using Work = Force x Distance. The work to stop a 925-kg car travelling at 95 km/h would be 255555 J.

What is the work done by brakes of a car of mass 1000 kg when its speed reduced from 20 Metre per second to 10?

Therefore, work done by the brake to reduce the speed will be equal to the change in kinetic energy of the car. Therefore, work done by the brakes will be 1.5×105 J 1.5 × 10 5 J .