What is a 0.12 kg ball moving at 6m s when it is hit by a bat?

What is a 0.12 kg ball moving at 6m s when it is hit by a bat?

Final answer: The magnitude of the change in momentum of a 0.12-kg ball that is hit by a bat and reverses direction from 6 m/s to 14 m/s, is 2.4 kg m/s.

Which has more momentum a truck that is parked or a falling raindrop?

Answer: The raindrop has more momentum because a supertanker at rest has zero momentum. The Penguins goalie Matt Murray stopped a slap shot traveling at 48.0 m/s in 0.02 s. The mass of the puck was 160 g.

What is the velocity of the 3 kg ball after the collision?

The velocity of the 3 kg ball is 4 m/s after the collision.

How do you calculate ball collision?

After the collision, the momentum is pf = mvf + MVf, and the kinetic energy is KEf = (1/2)mvf2 + (1/2)MVf2. So we have two equations: mvf + MVf = (M-m)Sqrt{2gh} (1/2)mvf2 + (1/2)MVf2 = (M+m)gh.

Does rain have momentum?

Answer and Explanation: When the rain falls from the sky with a certain velocity it has a certain value of momentum but as it hits the ground its velocity is reduced to zero and the momentum of the rain reduces to zero. In other words, the momentum of the rain is countered by the force exerted by the ground.

Which has greater momentum?

Momentum is directly proportional to the object’s mass and also its velocity. Thus the greater an object’s mass or the greater its velocity, the greater its momentum.

Which has greater momentum a truck at rest or a bicycle in motion?

Taking the formula for momentum to be p=mv this is the mass multiplied by the velocity. Although the semi truck certainly has a larger mass, it is not in motion and therefore does not have any momentum. The bicycle however has both mass and velocity and therefore has the larger momentum of the pair.

What are the SI units for momentum?

What is two body collision?

In physics, an elastic collision is an encounter (collision) between two bodies in which the total kinetic energy of the two bodies remains the same. In an ideal, perfectly elastic collision, there is no net conversion of kinetic energy into other forms such as heat, noise, or potential energy.

What is the law of conservation of momentum state?

The conservation of momentum states that, within some problem domain, the amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton’s laws of motion.

What is collision formula?

From the conservation of momentum, the equation for the collision between two objects is given by: m1v1 + m2v2 = m1v’1 + m2v’2. From this expression, the initial and final velocities can be derived.

What is collision in physics?

collision, in physics, the sudden, forceful coming together in direct contact of two bodies, such as, for example, two billiard balls, a golf club and a ball, a hammer and a nail head, two railroad cars when being coupled together, or a falling object and a floor.

Is momentum always conserved?

Momentum is always conserved because there is no external force acting on an isolated system (like the universe). Since momentum can never change, all of its components will always remain constant. Problems brought on by collisions should be resolved using the rule of conservation of momentum.

What is the KE of a 0.2 kg ball thrown with a velocity of 6m s?

The formula for kinetic energy is: KE = (1/2)mv^2 Now, we can plug in the values for mass and velocity: KE = (1/2)(0.2 kg)(6 m/s)^2 KE = (1/2)(0.2 kg)(36 m^2/s^2) KE = (0.1 kg)(36 m^2/s^2) KE = 3.6 kg m^2/s^2 So, the kinetic energy of the ball is $\boxed{3.6 \text{ J}}$ (Joules).

What is the potential energy of a ball of mass 2kg is thrown up with a speed of 10m s?

The correct answer is 100 J. We know that when the ball reaches the highest point, its whole kinetic energy is converted into Potential energy. ⇒ The potential energy of the ball at the highest point is 100 J.

What is the kinetic energy of a 2kg ball dropped from a height of 10m?

Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant. ∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m. ∴ Kinetic Energy = 980 J.

How much kinetic energy is needed to throw a 1 kg object to a height of 10 m?

E = mgh=(1)(9.8)(10)=98J. Was this answer helpful?