# How much work is done in accelerating a 2000 kg car from rest to a speed of 30m s?

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## How much work is done in accelerating a 2000 kg car from rest to a speed of 30m s?

900,000 J. The work done to accelerate a 2000 kg. car from rest to 30 m/s is equal to the change in kinetic energy of the car.

## How much work is required to accelerate 1000kg car from 20 m per second to 30 metre per second?

The work required to accelerate a 1000 kg car from 20 m/s to 30 m/s is equal to 250,000 joules.

## Which has greater kinetic energy a car travelling at 30 km h or a half as massive car travelling at 60 km h?

Expert-Verified Answer Where Ek = kinetic energy, m = mass, v = velocity. Ek = 450m J. Ek = 900m J. Thus , the car travelling at 60 km/hr at half mass has a greater kinetic energy to the car traveling at 30 km/hr at full mass.

## Does a car at rest have kinetic energy?

It has none. In order for a body to have kinetic energy, it must be moving.

## How to calculate acceleration?

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

## How much work is done to stop a car of weight 1500 kg moving with a velocity 60 km h?

Hence, work required to stop the car =12×1500×16.662 =208166.7J=208.17kJ. Was this answer helpful?

## What amount of work is done to stop a car of 1000 kg moving with a speed of 72 km per hour?

W = 1 2 × 1000 × 20 × 20 = 400000 J.

## How much work is done to move a 1400 kg car?

Hence, the work done against the friction =20300 J. A car weighing 1400 kg is moving at a speed of 54 km/h up a hill when the motor stops. If it is just able to reach the destination which is at a height of 10 m above the point, calculate the work done against friction (negative of the work done by the friction).

## How much work is required to stop a car of 1000 kg moving with speed of 72 km h?

Expert-Verified Answer Work required to stop a car is 400000 Joule or 400 kilojoule.

## What’s the formula for kinetic energy?

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

## Will a lighter car have a greater kinetic energy than a heavier car moving at the same speed?

This equation shows that kinetic energy is proportional to the mass of an object and the square of the velocity. Therefore, if two cars are driving down the street at the same speed, the heavier car will have more kinetic energy. Furthermore, faster-moving objects have more kinetic energy than slower objects have.

## What is the kinetic energy of a car at 30mph?

Kinetic Energy = ½ X mass X speed2 As the vehicle and the conditions are the same every time, we can effectively ignore the ½ X mass part of the equation. The differing speeds past point B can be said to be caused by speed alone. At 30mph our kinetic energy will be 30 X 30 = 900.

## How much net force is required to accelerate a 2000 kg car at 3.00 meters per second?

Thus, to accelerate the car at 3.00 m/s^2 of mass 2000 kg net force required is 6000 N.

## What is the rate of acceleration of a 2000 kg truck?

Therefore, the acceleration of a 2000 kg truck with a force of 2400 N is 2.1m/s².

## How much work is required to stop a car of 1000 kg with a speed of 72 km per hour?

W = 1 2 × 1000 × 20 × 20 = 400000 J.

## How do you calculate the work done on an object when you push it?

Work: Work is the energy exerted by an object as it applies a force to move another object over some distance. For a given amount of force, F, and a given distance, d, the work done on an object is given by the formula W = F ⋅ d .