# What amount of work is done to stop a car of 1000 kg moving with a speed of 72 km per hour?

## What amount of work is done to stop a car of 1000 kg moving with a speed of 72 km per hour?

W = 1 2 × 1000 × 20 × 20 = 400000 J.

## What is said to be done to increase the velocity of a car from 15 km per hour to 30 km per hour if the mass of the car is 1000 kg?

W=? ∴ Work done =337500 Joule.

## What is the KE of a 1000 kg car traveling at 60 km h?

Calculate the kinetic energy: KE = 0.5 * 1000 kg * 277.78 m^2/s^2 = 138890 J (Joules) So, the kinetic energy of the car is 138,890 Joules.

## How much work is done to move a 1400 kg car?

Hence, the work done against the friction =20300 J. A car weighing 1400 kg is moving at a speed of 54 km/h up a hill when the motor stops. If it is just able to reach the destination which is at a height of 10 m above the point, calculate the work done against friction (negative of the work done by the friction).

## How much force is needed to accelerate a 1000 kg car at a rate of 3 m 52?

hence, the force needed to accelerate the 1000kg car by 3m/s2 is 3000N .

## What is a bus of mass 10000 kg is moving with a velocity of 60 km h?

Expert-Verified Answer =1388500 Joules. Hope it helps you! Please mark me as the brainliest!

## How much work must be done to stop a 1000 kg car Travelling at 100km * H 1?

Hence, 385864 J work must be done to stop a traveling car.

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## What’s the formula for kinetic energy?

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

## What is the work done to increase the velocity of a car from 30 km h to 60 km h if the mass of the car is 1500 kg?

Answer: Work done is 156250 J.

## What is the formula for the velocity of a car?

Determine the object’s original velocity by dividing the time it took for the object to travel a given distance by the total distance. In the equation V = d/t, V is the velocity, d is the distance, and t is the time.

## What is the momentum of 1000 kg car moving northward at 20 m?

p = mv = (1000kg)(20m/s) = 20000 kg m/s, northward • c.

## What is the average braking force of a 1000 kg car moving at 20m s?

Therefore, the force applied by the brakes is 2000 N. Q. A car of mass 1000 kg moving with a velocity of 20 m/s is brought to rest by applying brakes in 10 seconds.

## What is the kinetic energy of a car of mass 1000 kg moving at 20 ms 1?

By using the equation: Kinetic Energy = (1/2)mv^2, using m as 1000kg and v as 20ms^-1. We can calculate this value as follows: KE = (1/2)(1000)(20)^2This is equal to 2.0*10^5J (solved using a scientific calculator).