What amount of work is done to stop a car of 1000 kg moving with a speed of 72 km per hour?

What amount of work is done to stop a car of 1000 kg moving with a speed of 72 km per hour?

W = 1 2 × 1000 × 20 × 20 = 400000 J.

What is said to be done to increase the velocity of a car from 15 km per hour to 30 km per hour if the mass of the car is 1000 kg?

W=? ∴ Work done =337500 Joule.

What is the KE of a 1000 kg car traveling at 60 km h?

Calculate the kinetic energy: KE = 0.5 * 1000 kg * 277.78 m^2/s^2 = 138890 J (Joules) So, the kinetic energy of the car is 138,890 Joules.

How much work is done to move a 1400 kg car?

Hence, the work done against the friction =20300 J. A car weighing 1400 kg is moving at a speed of 54 km/h up a hill when the motor stops. If it is just able to reach the destination which is at a height of 10 m above the point, calculate the work done against friction (negative of the work done by the friction).

How much force is needed to accelerate a 1000 kg car at a rate of 3 m 52?

hence, the force needed to accelerate the 1000kg car by 3m/s2 is 3000N .

What is a bus of mass 10000 kg is moving with a velocity of 60 km h?

Expert-Verified Answer =1388500 Joules. Hope it helps you! Please mark me as the brainliest!

How much work must be done to stop a 1000 kg car Travelling at 100km * H 1?

Hence, 385864 J work must be done to stop a traveling car.

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What’s the formula for kinetic energy?

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

What is the work done to increase the velocity of a car from 30 km h to 60 km h if the mass of the car is 1500 kg?

Answer: Work done is 156250 J.

What is the formula for the velocity of a car?

Determine the object’s original velocity by dividing the time it took for the object to travel a given distance by the total distance. In the equation V = d/t, V is the velocity, d is the distance, and t is the time.

What is the momentum of 1000 kg car moving northward at 20 m?

p = mv = (1000kg)(20m/s) = 20000 kg m/s, northward • c.

What is the average braking force of a 1000 kg car moving at 20m s?

Therefore, the force applied by the brakes is 2000 N. Q. A car of mass 1000 kg moving with a velocity of 20 m/s is brought to rest by applying brakes in 10 seconds.

What is the kinetic energy of a car of mass 1000 kg moving at 20 ms 1?

By using the equation: Kinetic Energy = (1/2)mv^2, using m as 1000kg and v as 20ms^-1. We can calculate this value as follows: KE = (1/2)(1000)(20)^2This is equal to 2.0*10^5J (solved using a scientific calculator).

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How do you calculate the amount of work done to stop a car of 1000 kg?

Expert-Verified Answer Work required to stop a car is 400000 Joule or 400 kilojoule. To convert km/hr into m/s , we multiply it by 5/18. Here, W is the work done.

What is the work done by brakes of a car of mass 1000 kg when its speed reduced from 20 Metre per second to 10?

Therefore, work done by the brake to reduce the speed will be equal to the change in kinetic energy of the car. Therefore, work done by the brakes will be 1.5×105 J 1.5 × 10 5 J .

What is the work required to be done to stop a car of 1200 kg moving with a velocity of 54 km per hour?

Expert-Verified Answer Thus the Work required to stop the car is -135,000 Joule or -135 kilo Joule.