# What is a 0.5 kg ball moving with a speed of 12 ms strikes?

**Contents**hide

## What is a 0.5 kg ball moving with a speed of 12 ms strikes?

A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle of 30° with the wall. It is reflected with the same speed and at the same angle. If the ball is in contact with the wall for 0.25 s, the average force acting on the wall is. 48 N.

## When a 5 kg ball is thrown upward with a speed of 10 ms?

(i) and (ii), mgh=250J or h=250Jmg=250J(5kg)(10m/s2)=5m.

## What is the momentum of a 6.0 kg bowling ball with a velocity of 2.2 ms?

p=6×2.2=13.2kg m/s. Q.

## When a body of mass 5 kg is thrown vertically upward with a speed of 10 meters per second?

= 1/2 × 5 × (10)² = 250 J. Ans. → Potential energy at the highest point= Kinetic energy lost by the body = 250 J.

## What is the formula of speed of falling ball?

The speed of the falling ball as a function of time is v = 9.8 (m/s2) t and the distance traveled is d = ½ 9.8 (m/s2) t2. In one second the ball travels 4.9 m. The velocity of the falling ball as a function of time is v = -9.8 (m/s2) t j and its position as a function of time is r = (4.9 m – ½ 9.8 (m/s2) t2) j.

## What is the maximum height of a 5kg ball thrown upwards with a speed of 10m s?

or h=250mg=250(5)(10)=5m.

## What is the momentum of a 4 kg ball?

A 4 kg ball has a momentum of 12 kg m/s.

## What is the momentum of 6.0 kg ball?

Mass of the ball = 6 kg. Velocity = 2.2 m/s. ∴ p = 13.2 kgms⁻¹. Hence, the momentum of the ball is 13.2 kgms⁻¹.

## What is the formula for momentum velocity?

p = m v . You can see from the equation that momentum is directly proportional to the object’s mass (m) and velocity (v). Therefore, the greater an object’s mass or the greater its velocity, the greater its momentum.

## How much work is done when 10 kg of mass is lifted to height of 5 m?

∴ Work done, W =Fs =98×5J=490J .

## What is an object of mass 5 kg is rotated in a horizontal plane by means?

– N= (5 x (3^2))/2. – N= (5 x 9)/2. – N= 45/2. – N= 22.5. Hence, when an object of 5Kg is rotated on a plane of radius 2m at a speed of 3ms, the centripetal force shall be 22.5N.

## What is the word done in lifting a mass 2 kg vertically through a height 10 m?

- = gain in PE of the given mass.
- = 2*g*10 [g = gravitational acceleration]
- = 2*9.81*10 [g = 9.81 m/s^2 (assumed)]
- = 196.2 (J) [Ans]

## What is the formula for speed ball?

The ball speed is calculated dividing the distance by the time. If the time was 3 seconds, the average speed will be 60/3 = 20 feet per second (6.1 m/sec).

## How do you measure the speed of a moving ball?

You take the distance traveled (for example 3 meters), and divide it by the time (three seconds) to get the speed (one meter per second). Calculating the speed of an object, therefore, requires you to measure a distance and the time it takes to travel that distance.

## How do you find velocity with which it strikes the ground?

## How much impulse is needed to stop a 10 kg bowling ball moving at 6m s?

Answer and Explanation: Therefore, the impulse needed to stop the bowling ball is − 60 k g m / s .