# What is the speed of the 2 kg cart after 5 seconds?

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## What is the speed of the 2 kg cart after 5 seconds?

The speed of the 2 kg cart after 5 seconds is 80.0 cm/s.

## What is the change in momentum of the cart?

For carts in an elastic collision, the change in momentum is the mass times the change in velocity. The impulse of a force is the product of the average force and the time interval during which the force acts.

## What is the speed of 2 kg ball having kinetic energy of 4 j?

The speed of the 2 k g ball having a kinetic energy of is 2 m s – 1 .

## What is the final velocity of the two carts after the collision?

For a perfectly elastic collision, the final velocities of the carts will each be 1/2 the velocity of the initial velocity of the moving cart. For a perfectly inelastic collision, the final velocity of the cart system will be 1/2 the initial velocity of the moving cart.

## What is the formula for gain in momentum?

Formula #1: Δp = m(Δv) The change in momentum (Δp) is equal to mass (m) multiplied by change in velocity (Δv). Use this formula when you know the mass of an object, as well as the velocity it gained or lost. The change in momentum (Δp) is expressed in kg m/s (kilogram meters per second).

## What is the formula for impulse Class 9?

The formula for calculating impulse: Then it is calculated by multiplying the force and that time. So, J= F*T. Here F represents force (in newton) and T represents time.

## What is the formula for momentum change and impulse?

The Impulse-Momentum Principle says I=mv−mu I = m v − m u which is final momentum – initial momentum so Impulse is the change in momentum.

## What is kinetic energy of 2kg 10m s?

The correct answer is 100 J. We know that when the ball reaches the highest point, its whole kinetic energy is converted into Potential energy.

## What is the formula for kinetic energy in KG?

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

## How much kinetic energy is needed to throw a 1 kg object to a height of 10 m?

E = mgh=(1)(9.8)(10)=98J. Was this answer helpful?

## How to find the velocity of the combined carts after collision?

After the collision, the combined (vector sums, use correct signs) of the two carts’ momentum must equal the incoming momentum. Since you have the mass and velocity of one of the two cars, and the mass of the other, you should be able to find the missing velocity: p = mrivri = mrfvrf + mbfvbf.

## How does the mass of the cart affect its acceleration?

If the mass of a cart increases, then the acceleration of the cart decreases when the force applied to the cart is held constant, because mass and acceleration are inversely proportional to each other according to Newton’s second law.

## Do the data for the second part of the experiment support or refute the second hypothesis?

The data for the second part of the experiment support the second hypothesis. As the mass of the cart increased, the acceleration of the cart decreased.