When a charged particle moves with velocity v?

When a charged particle moves with velocity v?

The force →F experienced by a particle of charge q moving with a velocity →v in a magnetic field →B is given by →F=q(→v×→B).

When a charged particle moving with velocity V enters a uniform electric and magnetic field?

A charged particle moving with a uniform velocity →v enters a region where uniform electric and magnetic fields →E and →B are present. It passes through the region without any change in its velocity.

When a charged particle moving with velocity V would the particle gain any energy?

Its direction is perpendicular to direction of motion of particle as well as perpendicular to the direction of magnetic field. Due to it, no work is done by the magnetic force on the charged particle. Therefore, the particle does not gain any kinetic energy.

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When a charged particle moving with velocity v goes unaccelerated?

Text solution `As the charged particle is not accelerated, the field E cannot be parallel to velocity . Hence, the velocity v is perpendicular to the electric field E .

What is the speed V of a particle?

A particle moves along a straight line and its velocity depends on time as v = 3t – t^2. Here, v is in m//s and t in second.

What is the velocity V of a particle?

The velocity v of a particle at time t is given by v=at+bt+c, where a,b and c are constant. The dimensions of a,b and c are respectively.

Why does the speed V of a charged particle moving in a magnetic field not change?

A magnetic field can only exert force on the charge perpendicular to the charge’s velocity vector. But force must be acute with velocity to speed an object up or obtuse to slow an object down. Since the force is perpendicular to velocity, the charge can’t change speed.

What is the electric charge moving with uniform velocity?

Therefore, the charge moving with a uniform velocity produces the magnetic field.

When an electron enters a uniform magnetic field with speed V?

Answer: The motion of an electron in a uniform magnetic field is circular, with the magnetic force providing the centripetal force. Since the electron enters the magnetic field with a velocity perpendicular to the field, it will follow a semicircular path and come out with the same speed as it entered.

When a particle of charge q and mass m moves with a constant velocity V?

A particle of mass m and charge q moves with constant velocity v along positive x−direction. It enters a region containing a uniform magnetic field B directed along the negative z−direction, extending from x=a to x=b. The minimum value of v required so that the particle can just enter the region x>b is: Q.

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What is the condition for velocity of a charged particle moving in across electric field and magnetic field without deflection?

When the strength of electric and magnetic fields are varied to get the forces due to electric and magnetic fields to be equal (FE = FB), then the charge can move in the field without any deflection.

Is a particle moving to the right when velocity is positive?

So if the velocity is denoted by v(t), we have v(t)=s′(t)=3t2−12t+9=3(t−1)(t−3). The particle is moving to the right when the velocity is positive, and to the left when the velocity is negative.

Under which condition a charged particle moving with velocity V goes undeflected?

A charged particle will go undeflected in the electric field and magnetic field if the direction of force on particle due to electric field only acts in the direction of motion of the particle, i.e., the charged particles moves parallel to the electric field and magnetic field acts parallel to the direction of motion …

Is a particle moving with velocity v is equal to k?

A particle is moving with a velocity →v=K (y^i+x^j), where K is a constant. The general equation for its path is: Q. A force →F=→v×→A is exerted on a particle in addition to the force of gravity, where →v is the velocity of the particle and →A is a constant vector in the horizontal direction.

What is the assertion when a charged particle moves with velocity V in a magnetic field?

Assertion (A): When a charged particle moves with velocity →v in a magnetic field →B (→v⊥→B), the force on the particle does no work. Reason ( R): The magnetic force is perpendicular to the velocity of the particle. Both Assertion (A) and Reason ( R) are true and Reason ( R) is the correct explanation of Assertion (A).

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When a particle of charge q and mass m moves with a constant velocity v?

A particle of mass m and charge q moves with constant velocity v along positive x−direction. It enters a region containing a uniform magnetic field B directed along the negative z−direction, extending from x=a to x=b. The minimum value of v required so that the particle can just enter the region x>b is: Q.

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